Chemistry - Nomenclature Question with Solution | TestHub

$\mathrm{DU}=3+8=11$; With 16 Cs , the formula of saturated compound must be ${\mathrm{C}}_{16}{\mathrm{H}}_{34}$. $\mathrm{DU}=\frac{34-(\mathrm{x}+1-2)}{2}\Rightarrow 11=\frac{35-\mathrm{x}}{2}\Rightarrow \mathrm{x}=13$

As there are two nitrogen atoms and 1 chlorine the formula of the compound must be ${\mathrm{C}}_{16}{\mathrm{H}}_{13}{\mathrm{ClN}}_2\mathrm{O}$