Chemistry - Nomenclature Question with Solution | TestHub

A benzene ring needs a DBE of at least 4. ${\mathrm{C}}_9{\mathrm{H}}_{12}$: DBE = (2 x 9 + 2 - 12) / 2 = 4, so it can (e.g. propylbenzene).

${\mathrm{C}}_7{\mathrm{H}}_{14}$ has DBE 1, ${\mathrm{C}}_8{\mathrm{H}}_{14}$ has 2 and ${\mathrm{C}}_{10}{\mathrm{H}}_{20}$ has 1.