Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptLaws of Chemical CalculationsMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension

A mixture of three gases an alkane (general formula ), an alkene (general formula ) and was subjected to sparking to cause combustion of both the hydrocarbon at . After the reaction three gases were present and none of the hydrocarbon remained. On passing the gases through KOH (absorb ), an increment in mass of KOH solution by 132 gm was observed. The remaining gases were passed over white anhydrous and the weight of blue hydrated crystals was found to be 72 gm more than that of white anhydrous . Given that initially total 10 moles of the three gases were taken and moles of alkane and alkene were equal and if molecular mass of alkene - molecular mass of alkane i.e. ), then answer the following questions. (Show calculations)

What are the number of moles of product gases.

Options:

Answer:
C
Solution:

KOH absorbs only CO₂, and its mass increases by 132 g.

Therefore, moles of CO₂ = .

Anhydrous CuSO₄ absorbs only H₂O, and its mass increases by 72 g.

Therefore, moles of H₂O = .

Hence, and .

 

Correct option: (C) ,

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Laws of Chemical Calculations
2mℹ️ Source: QB

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