Chemistry - Mole Concept Question with Solution | TestHub

In the reaction between ${\mathrm{KMnO}}_4$ and ${\mathrm{H}}_2{\mathrm{O}}_2,{\mathrm{KMnO}}_4$ acts as oxidising agent, changing to ${\mathrm{Mn}}^{2+}$ and ${\mathrm{H}}_2{\mathrm{O}}_2$ behaves as reducing agent oxidising to ${\mathrm{O}}_2$.

${\mathrm{MnO}}_4^{-}+{{\mathrm{H}}_2\mathrm{O}}_2⟶{\mathrm{Mn}}^{2+}+{\mathrm{O}}_2$

$n=5$ $n=2$

Equivalents of ${\mathrm{MnO}}_4^{-}$ = Equivalents of ${\mathrm{H}}_2{\mathrm{O}}_2$.

$25\times 10^{-3}$ $\times$$0.1$ = $10\times 10^{-3}$$\times$$N$

$N=0.25$

Volume strength of ${{\mathrm{H}}_2\mathrm{O}}_2=5.6\times 0.25=1.4$.