Chemistry - Mole Concept Question with Solution | TestHub

Let the molar mass of compound $=\mathrm{xg}$

No. of mole $=\frac{1}{\mathrm{x}}$

No. of moles of $\mathrm{C}=4\times \frac{1}{\mathrm{x}}$

Given : Moles of ${\mathrm{CO}}_2=\frac{0.88}{44}=\frac{1}{50}$

$\text{ ∴ Moles of }C=\frac{1}{50}$

Hence $4\times \frac{1}{x}=\frac{1}{50}$

$x=200$

ALITER :

Organic compound + O2 → CO₂ + H₂O

1 g 0.88 g

(containing 3 C-atoms

per molecule)

Applying POAC for C

4X moles of organic compound = 1 × Moles of CO₂

$4X\frac{1}{Molarmassoforganiccompound}=1\times \frac{0.88}{44}$

Molar mass of organic compound = 200