According to the equation: 4 N H 3 g + 5 O 2 g → 4 N O g + 6 H 2 O l ; when 1 mole of O 2 and 1 mole of ammonia are mixed, then

4 N H 3 ( g ) 4 m o l e s + 5 O 2 g 5 m o l e s → 4 N O ( g ) 4 m o l e s + 6 H 2 O ( l ) 6 m o l e s ∵ 4 moles of N H 3 ≅ 5 moles of O 2 1 moles of N H 3 ≅ 5 4 moles of O 2 ≅ 1.25 moles of O 2 thus, all volume of oxygen will be consumed.

Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

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According to the equation:
$4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (l)$ ;
when 1 mole of $O_{2}$ and 1 mole of ammonia are mixed, then

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Answer:

Solution:

$\underset{4 m o l e s}{4 N H_{3} (g)} + \underset{5 m o l e s}{5 O_{2} (g)} \to \underset{4 m o l e s}{4 N O (g)} + \underset{6 m o l e s}{6 H_{2} O (l)}$

$∵$ 4 moles of $N H_{3} ≅$ 5 moles of $O_{2}$

1 moles of $N H_{3} ≅ \frac{5}{4}$ moles of $O_{2} ≅$ 1.25 moles of $O_{2}$

thus, all volume of oxygen will be consumed.

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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