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ChemistryMole ConceptMiscellaneous/MixedMedium2 minQB

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Equivalent mass of $H_{3} PO_{2}$ when it disproportionates into $PH_{3}$ and $H_{3} PO_{3}$ is $($ Molecular mass $= M)$ :

Answer:

Solution:

$4 e + P^{+ 1} ⟶ P_{- 3}$

$\frac{[P^{+ 1} ⟶ P^{+ 3} + 2 e] \times 2}{3 P^{+ 1} \to 2 P^{+ 3} + P^{- 3}}$

So ,the total electrons lost or gained is 4 for 3 moles of H₃PO₂, so the $n$ -factor = $\frac{4}{3}$ .

Therefore, equivalent weight =

$Eq . wt . = \frac{M}{n - f a c t or} = \frac{M}{4/3} = \frac{3 M}{4}$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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