Chemistry - Mole Concept Question with Solution | TestHub

$4\mathrm{A}+2\mathrm{B}+3\mathrm{C}\to {\mathrm{A}}_4{\mathrm{B}}_2{\mathrm{C}}_3$
$1$$\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}$$0.6$$\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}$$\mathrm{}0.72$$\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}$
In the above reaction, reactant$\mathrm{\text{'}}\mathrm{C}\mathrm{\text{'}}\mathrm{}$will be the limiting reactant and it will decide yield product.
$\because$from$3$moles of$\mathrm{C}$;$1$mole product is formed
$\therefore$from$0.72$moles of$\mathrm{C}=\frac{1}{3}\times 0.72$
$=0.24$moles of product