Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediummultiple choice

2 mole of $CO_{2}$ is required to prepare:

Answer:

A, B, D

Solution:

Moles of Li₂CO₃ = $\frac{148}{74} = 2$ moles

Moles of NaHCO₃ = $\frac{168}{84} = 2$ moles

Moles of Ca(HCO₃)₂ = $\frac{162}{162} = 1$ moles

2 moles of NaHCO₃ are obtained from 2 moles of CO₂.

1 mole of Ca(HCO₃)₂ is obtained from 2 moles of CO₂.

2 moles of Li₂CO₃ are obtained from 2 moles of CO₂.

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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