Chemistry - Mole Concept Question with Solution | TestHub

$12\text{gm}$carbon contain =$6.023\times {10}^{23}$
${10}^{-23}\text{gm}\left(\text{1mg}\right)=\frac{6.023\times {10}^{23}}{12}\times {10}^{-3}$
$=0.502\times {10}^{20}$