Chemistry - Mole Concept Question with Solution | TestHub

Moles of K₂CO₃ in 50 ml solution = $0.2\times 50\times 10^{-3}=0.01$.

Moles of HNO₃ required = $0.02$.

$0.25$ moles of HNO₃ are present in $1000$ ml of HNO₃ solution.

$0.02$ moles of HNO₃ are present in:

$\frac{0.02}{0.25}\times 1000=80mlsolution$