Match the column- List - I (Concentration of aqueous solution) List - II (Density of given solutions is 1.2 g/ml) (A) 2 M NaOH solution (P) 16 gm solute in 240 gm solution (B) 8% ( V W ) KOH solutio

Question

Match the column- List - I (Concentration of aqueous solution) List - II (Density of given solutions is 1.2 g/ml) (A) 2 M NaOH solution (P) 16 gm solute in 240 gm solution (B) 8% ( V W ​ ) KOH solution (Q) 60 gm solute in 240 gm solution (C) 25% ( W W ​ ) CaCO 3 ​ solution (R) 8 gm solute in 100 ml solution (D) X C 3 ​ H 7 ​ OH ​ = 11 1 ​ (S) 30 gm solute in 100 ml solution (T) 1 mole solute in 400 gm solution

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Question Explanation: Match the column.

Concept: Concentration

(A) 2 M aq. NaOH solution ( $d = 1.2 g m / m l$ )

2 moles NaOH present in $1000 m l$ solution

or 2 moles NaOH ( $80 g m$ ) in $1200 g m$ solution.

$1000 m l so l u t i o n ⟶ 80 g m N a O H$

$100 m l so l u t i o n ⟶ 8 g m N a O H$

$1200 g m so l u t i o n ⟶ 80 g m$

$240 g m so l u t i o n ⟶ \frac{80}{1200} \times 240 = 16 g m N a O H$

(B) $8% \frac{W}{V}$ aq. KOH ( $d = 1.2 g m / m o l$ )

$8 g m K O H$ in $100 m l$ solution.

$8 g m K O H$ in $120 g m$ solution.

$16 g m K O H$ in $240 g m$ solution.

(C) $25% (\frac{W}{W})$ CaCO₃ solution ( $d = 1.2 g m / m l$ )

$100 g m$ solution contains $25 g m C a C O_{3}$ .

$400 g m so l u t i o n ⟶ 100 g m$ (1 mole) CaCO₃.

$240 g m so l u t i o n ⟶ \frac{25}{100} \times 240 = 60 g m C a C O_{3}$ .

$\frac{100}{1.2} m l so l u t i o n ⟶ 25 g m C a C O_{3}$ .

(D) $X_{C_{3} H_{7} O H} = \frac{1}{11} = \frac{1}{1 + 10}$

i.e., 1 mole C₃H₇OH + 10 mole H₂O

$↓ ↓$

$60 g m 180 g m$

$240 g m so l u t i o n = 200 m l so l u t i o n$

Chemistry - Mole Concept Question with Solution | TestHub

Options:

Doubts & Discussion

List - I (Concentration of aqueous solution)	List - II (Density of given solutions is 1.2 g/ml)
(A) 2 M NaOH solution	(P) 16 gm solute in 240 gm solution
(B) $8% (\frac{W}{V}) KOH$ solution	(Q) 60 gm solute in 240 gm solution
(C) $25% (\frac{W}{W}) CaCO_{3}$ solution	(R) 8 gm solute in 100 ml solution
(D) $X_{C_{3} H_{7} OH} = \frac{1}{11}$	(S) 30 gm solute in 100 ml solution
	(T) 1 mole solute in 400 gm solution