Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptLaws of Chemical CalculationsMedium2 minQB

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8.7 gm of pure $MnO_{2}$ is heated with an excess of HCl and the gas evolved is passed into a solution of KI. The amount of $I_{2}$ liberated is

Answer:

Solution:

MnO₂ + 4HCl → MnCl₂ + Cl₂ + H₂O

Cl₂ + 2KI → I₂ + 2KCl

Moles of MnO₂ = $\frac{8.7}{87} = 0.1$

Moles of Cl₂ = $0.1$

Moles of I₂ = $0.1$

Mass of I₂ = $0.1 \times 254 = 25.4$ gm.

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Laws of Chemical Calculations

⏱ 2mℹ️ Source: QB

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