Chemistry - Mole Concept Question with Solution | TestHub

Given: Mass of AgBr = $30.08g$

Moles of AgBr = $\frac{30.08}{108+80}=\frac{30.08}{188}=0.16$

So, moles of Br = $0.16mol$.

Mass of Br = $0.16\times 80=12.8g$

Mass of Cr = $14.88-12.8=2.08g$

Moles of Cr = $\frac{2.08}{52}=0.04$

Ratio Cr : Br = $0.04:0.16=1:4$

Empirical formula = CrBr₄ (A)

% Cr:

$$\frac{52}{52+320}\times 100=13.98\%$$

(C)

AgNO₃ used = AgBr formed = $0.16mol$ (D)

Correct Answer: A, C, D