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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

A 10 L flask contains 41.4 g of a mixture of gases C_xH₈and C_xH₁₂ . The total pressure of 44°C in the flask is 1.56 atm. Analysis revealed that the gas mixture has 87% by w% carbon. [Use : R = 0.082 atm-L/K-mole]

Calculate mole percent of $C_{x} H_{8}$ in the mixture.

Answer:

75.00

Solution:

Wt. of H in the mixture $= 8 a + 12 (0.6 - a)$

$= 7.2 - 4 a = 41.4 \times \frac{13}{100}$

$∴ a = 0.4545$

∴ mole $%$ of $C_{x} H_{8} = \frac{0.4545}{0.60} \times 100 = 75.75%$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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