Chemistry - Mole Concept Question with Solution | TestHub

Molarity (M)

$=\frac{\text{ Mass of solute (in }\mathrm{g})}{\text{ Molecular weight of solute }}=\frac{222\mathrm{g}}{111\mathrm{g}{\mathrm{mol}}^{-1}\times 1\mathrm{L}}\times$ volume of solution (in L$)$

[ $\because$ Molecular weight of ${\mathrm{CaCl}}_2=111\mathrm{g}{\mathrm{mol}}^{-1}$ ]

$=0.2\mathrm{mol}{\mathrm{L}}^{-1}=0.2\mathrm{M}$.