Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptLaws of Chemical CalculationsMedium2 minQB

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For the reaction,

$M^{x +} + MnO_{4}^{-} MO_{3}^{-} + M n^{2 +} + \frac{1}{2} O_{2}$

if one mole of $MnO_{4}^{-}$ oxidizes 1.67 moles of $M^{x +}$ to $MO_{3}^{-}$ , then the value of x in the metal ion is

Answer:

Solution:

Number of equivalents of MnO₄⁻ = number of equivalents of Mˣ⁺

$1 \times 5 = 1.67 \times n . f .$ $n . f . = 5 - x$

$\frac{5}{1.67} = 5 - x$

$2.994 \approx 3 = 5 - x$

$x = 2$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Laws of Chemical Calculations

⏱ 2mℹ️ Source: QB

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