Chemistry - Mole Concept Question with Solution | TestHub

1 mole benzoic acid will release 1 mole ${\mathrm{CO}}_2$ 11.2 $\mathrm{L}{\mathrm{CO}}_2$ at STP is $\frac{1}{2}{\mathrm{mole}}_{\mathrm{CO}}^2$ which will be released by reaction with $\frac{1}{2}$ mole benzoic acid $\begin{array}{rl}\text{ Mass of benzoic acid }& =\frac{1}{2}\times 122\\ & =61\mathrm{gm}\end{array}$