Chemistry - Mole Concept Question with Solution | TestHub

Target Substance: $1mol$ of C₂H₄O₂ has a molar mass of $60g/mol$ (corresponding to entry R in Column-I).

Column-II Match: The mass percentage of Oxygen is calculated as $\%O=\left(\frac{32g}{60g}\right)\times 100=\frac{160}{3}\%$, which matches entry (3).

Column-III Match: The ratio of moles is $\frac{MolesofH}{MolesofC}=\frac{4}{2}=\frac{2}{1}$, which matches entry (iv).

Conclusion: Combining Column-II and Column-III for this substance gives 3 - iv, making (A) the correct option.