Calculate % yield of the reaction if 200g KHCO 3 produces 22 g of CO 2 upon strong heating. 2 KHCO 3 → K 2 CO 3 + H 2 O + CO 2 [If your answer is greater than 9, then add all the digits.

Question

Calculate % yield of the reaction if 200g $KHCO_{3}$ produces 22 g of $CO_{2}$ upon strong heating.

$2 KHCO_{3} \to K_{2} CO_{3} + H_{2} O + CO_{2}$

[If your answer is greater than 9, then add all the digits.

Example: Ans. 12 then fill $1 + 2 = 3$ , Ans. 123 then fill $1 + 2 + 3 = 6$ , & Ans. 20 then fill $2 + 0 = 2$ ]

TestHub · Accepted Answer

2 KHCO 3 ​ → K 2 ​ CO 3 ​ + H 2 ​ O + CO 2 ​ 200 g mole = 100 200 ​ = 2 1 mol of CO 2 ​ mass of CO 2 ​ = 44 g % yield ​ = Theoretical yield actual yield ​ × 100 ​ = 44 22 ​ × 100 = 50% ​

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