Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleEasy2 minQB

ChemistryEasyinteger

Calculate % yield of the reaction if 200g $KHCO_{3}$ produces 22 g of $CO_{2}$ upon strong heating.

Answer:

Solution:

$2 KHCO_{3} \to K_{2} CO_{3} + H_{2} O + CO_{2}$

200 g mole $= \frac{200}{100} = 2 m o l$

1 mol of

CO_{2}

= 44 g

% yield = \frac{actual yield}{Theoretical yield} \times 100 = \frac{22}{44} \times 100 = 50%

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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