Chemistry - Mole Concept Question with Solution | TestHub

For mole of given acid${\mathrm{C}}_2{\mathrm{O}}_4^{2-}$present = 1 mole

So${\mathrm{C}}_2{\mathrm{O}}_4^{2-}\to \mathrm{C}{\mathrm{O}}_2+2{\mathrm{e}}^{-}$

So n-factor for${\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4.\text{2}{\text{H}}_2\mathrm{O}$as a reducing agent = 2

Equivalent weight (E)$=\frac{\mathrm{M}}{2}=\frac{126}{2}=63$

250 ml of centinormal solution (NV)$=\frac{250}{100}\times 10^{-3}$equivalent

So Weight of${\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4.\text{2}{\text{H}}_2\mathrm{O}$required (W)$=\mathrm{N}\mathrm{V}\mathrm{E}=\frac{250}{100}\times 10^{-3}\times \text{63}=0.\text{1575 g}$