For calculation of molecular weight of a dibasic acid using silver salt method, when a graph is plotted between weight of silver salt and weight of Ag, a straight line is obtained as shown. Find molecular weight of acid (Take $3 = 1.7, Ag 108$ )

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The slope is tan 6 0 ∘ = 3 ​ = 1.7 = W A g − s a lt ​ W A g ​ ​ . For a dibasic acid, the silver salt is M − 2 + 2 ( 108 ) = M + 214 , while the Ag present is 2 × 108 = 216 . 216 M + 214 ​ = 1.7 M + 214 = 367.2 ⟹ M = 153.2 g m o l − 1

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