Nicotine, a compound contains carbon, hydrogen and nitrogen in 60 : 7 : 14 ratio by mass. If its molecular weight is 162, then atomicity of nicotine is.

Question

TestHub · Accepted Answer

Given mass ratio of C : H : N = 60 : 7 : 14

Convert into moles:

$\frac{60}{12} : \frac{7}{1} : \frac{14}{14} = 5 : 7 : 1$

Empirical formula = C₅H₇N

Empirical formula mass:

$= 5 (12) + 7 (1) + 14 = 81$

Given molecular mass = 162

$n = \frac{162}{81} = 2$

Molecular formula:

$(C_{5} H_{7} N)_{2} = C_{10} H_{14} N_{2}$

Atomicity = $10 + 14 + 2 = 26$

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