What volume of H 2 S gas measured at 1.0 atm and 0 ∘ C is produced when 16.6 g of KI reacts with excess of H 2 SO 4 ? K I + H 2 SO 4 → K 2 SO 4 + I 2 + H 2 S + H 2 O

Question

What volume of H 2 ​ S gas measured at 1.0 atm and 0 ∘ C is produced when 16.6 g of KI reacts with excess of H 2 ​ SO 4 ​ ? K I + H 2 SO 4 &#x2192; K 2 SO 4 + I 2 + H 2 S + H 2 O

TestHub · Accepted Answer

Moles of KI reacted = 166 16.6 ​ = 0.1 Equivalents of KI reacted = 0.1 [∵ n-factor of KI = 1] ∴ Equivalents of H₂S formed = 0.1 Moles of H₂S formed = 8 0.1 ​ [∵ n-factor of H₂S = 8] Volume of H₂S at 1.0 atm and 0°C = 8 0.1 ​ × 22400 mL = 280 mL.

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