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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediumsingle choice

A one litre solution of 0.1 M of a metal chloride $MCl_{x}$ requires 500 mL of $0.6 M AgNO_{3}$ solution for complete precipitation. The value of x is

Options:

Answer:

Solution:

$MC l_{x} + x A g N O_{3} ⟶ M (N O_{3})_{x} + x A g Cl$

molar ratio $1 : x :: 1 : x$ .

Moles of $A g N O_{3} = \frac{0.6}{1000} \times 500 = 0.3$ .

Moles of $MC l_{x}$ $0.1$

Since $0.3$ moles of $A g N O_{3}$ are precipitated by $0.1$ mol of salt .

Therefore, the value of $x = 3$ .

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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