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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediumsingle choice

Density of a 2.05 M solution of acetic acid in water is $1.02 g / ml$ . The molality of the solution is (Atomic mass: $H = 1, C = 12, O = 16$ )

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Answer:

Solution:

Molality $= \frac{1000 \times M}{1000 \times d - ( M M _{1} )} = \frac{1000 \times 2.05}{1000 \times 1.02 - ( 2.05 \times 60 )} = 2.28 m o l k g^{- 1}$ .

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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