Assertion : 11 22 Mg emits a positron giving 12 22 Mg . Reason : In β + emission neutron is transformed into proton.

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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptAtomic mass/Average Atomic Mass/Average Molecular MassEasy2 minPYQ_2003

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Assertion : $_{11}^{22} Mg$ emits a positron giving $\frac{22}{12} Mg$ . Reason : In $β^{+}$ emission neutron is transformed into proton.

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$_{11} Na^{22} \to_{12} Mg^{22} +_{- 1} β^{0}$ It involves $β$ -particle emission. While positron emission is due to the conversion of proton into neutron. $_{1}^{1} p \to_{0}^{1} n +_{1}^{0} β$

Stream:AIIMSSubject:ChemistryTopic:Mole ConceptSubtopic:Atomic mass/Average Atomic Mass/Average Molecular Mass

⏱ 2mℹ️ Source: PYQ_2003

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