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A 6.90 M solution of KOH in water has $30%$ of KOH by weight. The density of solution is

Answer:

Solution:

Weight of $KOH = 6.9 \times 56 = \frac{30}{100} \times$ weight of solution

Therefore, weight of solution $= \frac{6.9 \times 56}{0.3} = 1288$ g.

Therefore, density of solution $= \frac{1288}{1000} g / m l = 1.288 g / m l$ .

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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