Chemistry - Mole Concept Question with Solution | TestHub

Let the weight of the metal be $100g$, and thus the weight of nitrogen with which it combines is $14g$.

$3M+\frac{x}{2}{N}_2⟶{}_{}{M}_3{N}_x$

$n=6$

$E=\frac{28}{6}=\frac{14}{3}$

Therefore, $14g$ of nitrogen combines with $100g$ of metal.

Thus, $\frac{14}{3}g$ of nitrogen combines with

$\frac{100}{14}\times \frac{14}{3}=\frac{100}{3}=33.33gofmetal$

The equivalent mass of the metal =$33.33$.