Chemistry - Mole Concept Question with Solution | TestHub

$\text{ No. of atoms }=\frac{\text{ Massin }g}{\mathrm{Molar}\mathrm{Mas}(\mathrm{g}/\mathrm{mol})}\times {\mathrm{N}}_{\mathrm{A}}$
Therefore for the same Mass element having the least Molar mass will have the higher no. of atoms.
- ${\mathrm{M}}_{\mathrm{Po}}=209$
- ${\mathrm{M}}_{\mathrm{Pr}}=141$
- ${\mathrm{M}}_{\mathrm{Pb}}=207$
- ${\mathrm{M}}_{\mathrm{Pt}}=195$