Calculate number of moles present in 9.10 × 1 0 − 2 kg of water.

Mass of water = 9.10 × 1 0 − 2 kg = 91 g Molar mass of water ( H 2 O ) = 18 g mol − 1 Number of moles = Molar mass Mass = 18 91 ≈ 5.05 moles The closest value among the given options is 5.0 . Answer: 5.0

Start Free Mock LoginAlready registered? Login here

Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2024

ChemistryEasysingle choice

Calculate number of moles present in $9.10 \times 1 0^{- 2} kg$ of water.

Options:

Answer:

Solution:

Mass of water $= 9.10 \times 1 0^{- 2} kg = 91 g$

Molar mass of water ( $H_{2} O$ ) $= 18 g mol^{- 1}$

Number of moles $= \frac{Mass}{Molar mass} = \frac{91}{18} \approx 5.05 moles$

The closest value among the given options is $5.0$ .

Answer: 5.0

Stream:MHT_CETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2024

Doubts & Discussion

Loading discussions...