Chemistry - Mole Concept Question with Solution | TestHub

Solute in 200 g of 30% solution$=60$g
Solute in 300 g of 20% solution$=60$g
total grams of solute$=120$g
total grams of solution$=200+300=500$g
% of solute in the final solution$=\frac{\text{Wt. of solute}}{\text{Wt. of solution}}\times 100$
% of solute in the final solution$=\frac{120}{500}\times 100=24\mathrm{\%}$