Chemistry - Mole Concept Question with Solution | TestHub

Let weight of metal oxide$=100\text{g}$
Weight of oxygen$=32\text{g}$
$\therefore$Weight of metal$=100-32=68\text{g}$
Equivalent weight of metal in oxide$=\frac{\text{wt}\text{.}\text{of}\text{metal}}{\text{wt}\text{.}\text{of}\text{oxygen}}\times 8=\frac{68}{32}\times 8=17$.