Chemistry - Mole Concept Question with Solution | TestHub

Let the mass of oxygen be$x$gm

$\therefore$Mass of nitrogen =$4x$gm

Number of molecules = 6.023 x 10²³x number of moles

$\therefore \text{Ratio}=\frac{\text{6.023}\times 10^{23}\times \text{no. of moles of oxygen}}{\text{6.023}\times 10^{23}\times \text{no. of moles of nitrogen}}$

$=\frac{\frac{{\text{m}}_{{\text{O}}_2}}{{\text{M}}_{{\text{O}}_2}}}{\frac{{\text{m}}_{{\text{N}}_2}}{{\text{M}}_{{\text{N}}_2}}}=\frac{\frac{x}{32}}{\frac{4x}{28}}$

$=\frac{7}{32}=\text{7 : 32}$