Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediummultiple choice

Equal masses of $SO_{2}$ and $O_{2}$ are placed in a flask at STP. Choose the correct statement.

Answer:

A, B, C

Solution:

Let the equal mass of both gases be $w$ grams. The moles are $n_{S O_{2}} = \frac{w}{64}$ and $n_{O_{2}} = \frac{w}{32}$ .

Statements A and B are correct because moles of O₂ are double those of SO₂, meaning O₂ has more molecules and occupies more volume at STP.

Statement C is correct because the ratio of total atoms is:

$(3 \times \frac{w}{64}) : (2 \times \frac{w}{32}) = \frac{3}{64} : \frac{4}{64} = 3 : 4$

Statement D is incorrect since $n_{S O_{2}} < n_{O_{2}}$ .

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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