Chemistry - Mole Concept Question with Solution | TestHub

$\underset{\underset{\underset{0.029\text{mol}}{\frac{6.5}{224}\text{mol}}}{}}{\text{PbO}}+\underset{\underset{\underset{0.087\text{mol}}{\frac{3.2}{36.5}\text{mol}}}{}}{2\text{HCl}}\to \underset{}{{\text{PbCl}}_2}+{\text{H}}_2\text{O}$
Formation of moles of lead (II) chloride depends upon the number of moles of PbO which acts as a limiting factor here. So, number of moles of$\mathrm{P}\mathrm{b}\mathrm{C}{\mathrm{l}}_2$formed will be equal to the number of moles of PbO i.e. 0.029.