Start Free Mock LoginAlready registered? Login here

Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

3 g of $H_{2}$ react with 29 g of $O_{2}$ to form $H_{2} O$ . Find the amount of the reactant left unreacted?

Options:

Answer:

Solution:

$\underset{\underset{= 4.032}{2 \times 2.016}}{2 H_{2}} + \underset{32 g}{O_{2}} \to \underset{\underset{= 36.032}{2 \times (2.016 + 16)}}{2 H_{2} O}$

3 g of $H_{2}$ require $O_{2} = \frac{32}{4.032} \times 3 = 23.8 g$

$O_{2}$ left unreacted $= 29 - 23.8 = 5.2 g$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...