Chemistry - Mole Concept Question with Solution | TestHub

Mole of ${\mathrm{N}}_2=\frac{2800}{28}=100$ & ${\mathrm{H}}_2=\frac{1000}{2}=500$

$\begin{array}{c}\\ \mathrm{Initial}\mathrm{mole}\\ \mathrm{Final}\mathrm{mole}\end{array}\begin{array}{c}{\mathrm{N}}_2\left(\mathrm{g}\right)\\ 100\\ 0\end{array}\begin{array}{c}+\\ \\ \end{array}\begin{array}{c}3{\mathrm{H}}_2\left(\mathrm{g}\right)\\ 500\\ 500-300\end{array}\begin{array}{c}\to \\ \\ \end{array}\begin{array}{c}2{\mathrm{NH}}_3\left(\mathrm{g}\right)\\ \mathrm{Limiting}\mathrm{reagent}\mathrm{is}{\mathrm{N}}_2\\ 200\end{array}$

Mass of ${\mathrm{NH}}_3$ formed $=200\times 17=3400\mathrm{gram}$