Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

When 22.4 litres of $H_{2} (g)$ is mixed with 11.2 litres of $C l_{2} (g)$ , each at S.T.P., the moles of HCl (g) formed is equal to

Answer:

Solution:

$n_{H_{2}} = \frac{V (L)}{22.4 L} = \frac{22.4}{22.4} = 1$
$n_{C l_{2}} = \frac{11.2}{22.4} = 0.5$ mole

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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