Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

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$200 ml, 2 M Li_{3} PO_{4}$ solution is $80%$ ionised then find sum of mol of all ions in solution -

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Answer:

Solution:

Question Explanation: Find the sum of moles of ions.

Concept: This question is based on molarity.

Solution:

$m o l es = L i_{3} P O_{4} \frac{2 \times 200}{1000} = 0.4 ⟶ 3 L i^{+} - + P O_{4}^{3 -} - 80% i o ni se d = 0.4 - 0.4 \times \frac{80}{100} 3 \times 0.32 0.32 = 0.4 - 0.32 = 0.08 0.96 0.32 T o t a l m o l eso f L i^{+} + P O_{4}^{3 -} = 0.96 + 0.32 = 1.28 m o l es$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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