Chemistry - Mole Concept Question with Solution | TestHub

Molar mass of$\text{C}{\text{O}}_2=12+32=44$

$\because \frac{\text{W}}{\text{M}}=\frac{\text{Number of molecules }}{{\text{N}}_{\mathrm{A}}}\left(\text{for}\text{C}{\text{O}}_2\right)$

$\frac{4.4}{44}=\frac{\text{Number of molecules}}{6\times 10^{23}}$

$\therefore$Number of molecules in$\text{C}{\text{O}}_2=\frac{4.4\times 6\times 10^{23}}{44}$

$=0.1\times 6\times 10^{23}=6\times 10^{22}$

$\text{Number of oxygen atoms }=2$times of$6\times 10^{22}$

($\because$Each$\text{C}{\text{O}}_2$contains two oxygen atoms)

$\therefore \text{Number of }\left(\text{oxygen atom }\right)=2\times 6\times 10^{22}=1.2\times 10^{23}$