An unknown compound A C 8 H 10 O 3 on acetylation with C H 3 C O C l / P y forms acetyl derivative of A whose MW is 280. A on treat with C H 2 N 2 gives methyl ether of B having MW 182. If the number

Question

An unknown compound A C 8 H 10 O 3 on acetylation with C H 3 C O C l / P y forms acetyl derivative of A whose MW is 280. A on treat with C H 2 N 2 gives methyl ether of B having MW 182. If the number of phenolic hydroxyls and alcoholic hydroxyls in the compound A are X and Y respectively. Find the sum of X + Y here?

TestHub · Accepted Answer

Number of hydroxyl group by acetylation method $= \frac{280 - MW of C_{8} H_{10} O_{3}}{42}$
$= \frac{280 - 154}{42} = \frac{126}{42} = 3$
Number of phenolic hydroxyl $= \frac{MW of methyl ether - MW}{14}$
$= \frac{182 - 154}{14} = \frac{28}{14} = 2$
Hence, X = 2
Number of alcoholic $- O H$ groups $= 3 - 2 = 1$
Hence, Y = 1
So X + Y = 2 + 1 = 3.

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