A sample of calcium carbonate has the following percentage composition. Ca = 40% , C = 12% and 0 = 48% According to law of definite proportion the weight of calcium in 4 g of a sample of calcium carbo

Question

A sample of calcium carbonate has the following percentage composition. $Ca = 40%, C = 12%$ and $0 = 48%$ According to law of definite proportion the weight of calcium in $4 g$ of a sample of calcium carbonate from another source will be (at. no. $Ca = 40, C = 40, C = 12, 0 = 16$ )

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Answer:

B

Solution:

(A) In $100 g$ of $CaCO_{3}, 40 g Ca$ is present $∴$ In $4 g$ of $CaCO_{3} = \frac{4 \times 40}{100} = 1.6 g$ of $Ca$ is present.

TestHub · Accepted Answer

(A) In 100 g of CaCO 3 ​ , 40 g Ca is present ∴ In 4 g of CaCO 3 ​ = 100 4 × 40 ​ = 1.6 g of Ca is present.

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