Chemistry - Mole Concept Question with Solution | TestHub

$\begin{array}{cccccc}& 2{\text{Al}}_{}& +& 3{\text{Cl}}_2& \to & 2{\text{AlCl}}_3\left(\text{s}\right)\\ \text{Moles before reaction}& \text{1}\text{.0}& & \text{3}\text{.0}& & \text{0}\\ \text{Moles after reaction}& \text{0}& & \text{1}\text{.5}& & \text{1}\text{.0}\end{array}$

Mole ratio for reactants and products are$2\mathrm{ }:\mathrm{ }3\mathrm{ }:\mathrm{ }2$

Thus limiting reagent is$\mathrm{A}\mathrm{l}$.

Moles of$\mathrm{A}\mathrm{l}\mathrm{C}{\mathrm{l}}_3$formed$=\mathrm{ }1.0$

Moles of excess reagent$\mathrm{C}{\mathrm{l}}_2$left unreacted$=1.5$