At STP, 2.8 litres of hydrogen sulphide were mixed with 1.6 litres of sulphur dioxide and the reaction occurred according to the equation
$2 H_{2} S (g) + S O_{2} (g) \to 2 H_{2} O (l) + 3 S (s)$
Which of the following shows the volume of the gas remaining after the reaction?

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TestHub · Accepted Answer

So, Sol 2 vol H 2 S ≡ 1 vol SO 2 or 2 .8 L H 2 S = 1 .4 L SO 2 Hence, after reaction, volume of remaining S O 2 = 1.6 − 1.4 L = 0.2 L

Chemistry - Mole Concept Question with Solution | TestHub

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