In a compound C , H and N are present in 9 : 1 : 3 . 5 by weight. If molecular weight of compound is 108 , the molecular formula of compound is

Question

TestHub · Accepted Answer

$∴$ Empirical formula $= C_{3} H_{4} N$

The empirical formula mass $= 3 \times 12 + 4 \times 1 + 14 = 54 g$

Given, molecular mass $= 108 g$

Thus, $n = \frac{108}{54} = 2$

Hence, molecular formula = (Empirical formula) $\times 2$

$(C_{3} H_{4} N) \times 2 = C_{6} H_{8} N_{2}$

Chemistry - Mole Concept Question with Solution | TestHub