Chemistry - Mole Concept Question with Solution | TestHub

Density of$\mathrm{H}\mathrm{C}\mathrm{l}=1.\text{25 g m}{\text{L}}^{}$solution$-1$

Weight of 100 mL solution = 125 g

For a 29.2 %$\left(\mathrm{w}/\mathrm{w}\right)$$\mathrm{H}\mathrm{C}\mathrm{l}$solution, weight$=\frac{125}{100}\times 29.2=36.5$gm

So in 100 mL solution, moles of$\mathrm{H}\mathrm{C}\mathrm{l}$$=\frac{36.5}{36.5}=1$moles

So molarity of$\mathrm{H}\mathrm{C}\mathrm{l}=10\mathrm{ }\mathrm{M}$

Using${\mathrm{M}}_1{\mathrm{V}}_1={\mathrm{M}}_2{\mathrm{V}}_2$

Volume required$={\mathrm{V}}_2\times 10=200\times 0.4$

${\mathrm{V}}_2=\text{8 mL}$