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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedHard2 minPYQ_2014

ChemistryHardsingle choice

When $22.4$ litres of $H_{2} (g)$ is mixed with $11.2$ litres of $C l_{2} (g),$ each at STP, the moles of $H C l (g)$ formed is equal toNEET 2014

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Answer:

Solution:

$\begin{matrix} \underset{22.4 lt}{H_{2}} + & \underset{11.2 lt}{C l_{2}} \to & 2 H C l \end{matrix}$
$\begin{matrix} 1 m o l e & = \frac{1}{2} m o l e \end{matrix}$
Limiting reagent is $C l_{2} .$ So, $1$ mole $H C l$ is formed.

Stream:NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2014

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