Chemistry - Mole Concept Question with Solution | TestHub

Silver carbonate on being strongly heated decomposes as $\begin{array}{ll}{\mathrm{Ag}}_2{\mathrm{CO}}_3\stackrel{\Delta }{⟶}& 2\mathrm{Ag}+{\mathrm{CO}}_2+\frac{1}{2}{\mathrm{O}}_2\\ 276\mathrm{g}& 216\mathrm{g}\end{array}$ As $276\mathrm{g}$ of ${\mathrm{Ag}}_2{\mathrm{CO}}_3$ gives $=216\mathrm{g}$ of $\mathrm{Ag}$ Hence, $2.76\mathrm{g}$ of ${\mathrm{Ag}}_2{\mathrm{CO}}_3$ will give $=\frac{2.76\times 216}{276}=2.16\mathrm{g}$