What mass of Zn in kg will be obtained from an ore containing 225 kg of ZnS ?
(Zn = 65 , S = 32, O = 16)

Question

What mass of Zn in kg will be obtained from an ore containing 225 kg of ZnS ? (Zn = 65 , S = 32, O = 16)

TestHub · Accepted Answer

The overall reaction from ZnS to Zn is:

ZnS → Zn

Molar mass of ZnS = $65 + 32 = 97$ g/mol

Molar mass of Zn = $65$ g/mol

From the stoichiometry, 1 mole of ZnS yields 1 mole of Zn.

Therefore, 97 kg of ZnS yields 65 kg of Zn.

Mass of Zn obtained from 225 kg of ZnS:

Mass of Zn = $\frac{65 k g Z n}{97 k g Z n S} \times 225 k g Z n S$

Mass of Zn = $\frac{65}{97} \times 225$ kg

Mass of Zn = $0.6701 \times 225$ kg

Mass of Zn = $150.77$ kg

The mass of Zn obtained is approximately 150.77 kg.

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